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a^2+a^2=56.25
We move all terms to the left:
a^2+a^2-(56.25)=0
We add all the numbers together, and all the variables
2a^2-56.25=0
a = 2; b = 0; c = -56.25;
Δ = b2-4ac
Δ = 02-4·2·(-56.25)
Δ = 450
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{450}=\sqrt{225*2}=\sqrt{225}*\sqrt{2}=15\sqrt{2}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-15\sqrt{2}}{2*2}=\frac{0-15\sqrt{2}}{4} =-\frac{15\sqrt{2}}{4} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+15\sqrt{2}}{2*2}=\frac{0+15\sqrt{2}}{4} =\frac{15\sqrt{2}}{4} $
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